(lg根号27+lg5-lg10根号2)/lg1.5
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/22 03:56:24
(lg根号27+lg5-lg10根号2)/lg1.5
![(lg根号27+lg5-lg10根号2)/lg1.5](/uploads/image/z/8136887-23-7.jpg?t=%EF%BC%88lg%E6%A0%B9%E5%8F%B727%2Blg5-lg10%E6%A0%B9%E5%8F%B72%EF%BC%89%2Flg1.5)
(lg√27+lg5-lg10√2)/lg1.5={(3/2)lg3+(1-lg2)-[1+(1/2)lg2]}/(lg3-lg2)=(3/2)(lg3-lg2)/(lg3-lg2)=3/2
(lg根号27+lg5-lg10根号2)/lg1.5
【根号lg9-lg9+lg10×(lg根号27+lg8-lg根号1000)】÷(lg0.3)(lg1.2)
(lg根号27+lg8-lg根号1000)/lg1、2
化简:(1)4lg2+3lg5-lg五分之一,(2)(lg根号下27+lg8-lg根号下1000)比上(lg1.2)
2(lg根号2)²+lg根号2*lg5+lg(5根号2)=?
【lg(根号下27)+lg8-3(lg根号下10)】÷lg1.2=?
化简:(lg根号27+lg8-lg根号1000)/lg1.2
求(lg根号27+lg8-3lg根号10)/lg1.2
计算 (lg根号27+lg8-lg根号1000)/lg1.2
计算:(lg根号下27+lg8-lg根号下1000)\lg1.2
急(lg根号下27+lg8-lg根号下1000)\lg1.2=(3/2lg3+3lg2-3/2)/lg1.2然后呢
(lg根号27+lg8-3lg根号10)除以lg1.2