计算:(lg根号下27+lg8-lg根号下1000)\lg1.2
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/27 07:37:34
计算:(lg根号下27+lg8-lg根号下1000)\lg1.2
![计算:(lg根号下27+lg8-lg根号下1000)\lg1.2](/uploads/image/z/14967556-52-6.jpg?t=%E8%AE%A1%E7%AE%97%EF%BC%9A%EF%BC%88lg%E6%A0%B9%E5%8F%B7%E4%B8%8B27%2Blg8-lg%E6%A0%B9%E5%8F%B7%E4%B8%8B1000%EF%BC%89%5Clg1.2)
解; (lg√27+lg8-lg√1000)/lg1.2
=(lg3^3/2+lg2^3-lg10^3/2)/lg1.2
=(3/2lg3+3lg2-3/2lg2-3/2lg5)/lg1.2
=(3/2lg3+3/2lg2-3/2lg5)/lg1.2
=3/2(lg3+lg2-lg5)/lg1.2
=3/2(lg6-lg5)/lg1.2
3/2lg6/5/lg1.2
=3/2lg1.2/lg1.2
=3/2
=(lg3^3/2+lg2^3-lg10^3/2)/lg1.2
=(3/2lg3+3lg2-3/2lg2-3/2lg5)/lg1.2
=(3/2lg3+3/2lg2-3/2lg5)/lg1.2
=3/2(lg3+lg2-lg5)/lg1.2
=3/2(lg6-lg5)/lg1.2
3/2lg6/5/lg1.2
=3/2lg1.2/lg1.2
=3/2
计算:(lg根号下27+lg8-lg根号下1000)\lg1.2
(lg根号27+lg8-lg根号1000)/lg1、2
【lg(根号下27)+lg8-3(lg根号下10)】÷lg1.2=?
计算 (lg根号27+lg8-lg根号1000)/lg1.2
急(lg根号下27+lg8-lg根号下1000)\lg1.2=(3/2lg3+3lg2-3/2)/lg1.2然后呢
化简:(1)4lg2+3lg5-lg五分之一,(2)(lg根号下27+lg8-lg根号下1000)比上(lg1.2)
根号下{(lg3)平方-lg9+1}乘以(lg根号下27+lg8-lg根号下1000)再整体除以lg0.3乘以lg1.2
化简:(lg根号27+lg8-lg根号1000)/lg1.2
【根号lg9-lg9+lg10×(lg根号27+lg8-lg根号1000)】÷(lg0.3)(lg1.2)
求(lg根号27+lg8-3lg根号10)/lg1.2
(lg根号下27+lg8-lg根号下1000)/(1/2lg0.3+lg2)
【根号(lg的平方3-lg9+1)*(lg根号27+lg8-lg根号1000)】/(lg0.3)*(lg1.2)