已知3cos(2x+y)+5cosy=0,则tan(x+y)tanx的值是
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已知3cos(2x+y)+5cosy=0,则tan(x+y)tanx的值是
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![已知3cos(2x+y)+5cosy=0,则tan(x+y)tanx的值是](/uploads/image/z/5420482-34-2.jpg?t=%E5%B7%B2%E7%9F%A53cos%EF%BC%882x%2By%EF%BC%89%2B5cosy%3D0%2C%E5%88%99tan%28x%2By%29tanx%E7%9A%84%E5%80%BC%E6%98%AF)
cos(2x+y)=cos[(x+y)+x]
=cos(x+y)cosx-sin(x+y)sinx
cosy=cos[(x+y)-x]
=cos(x+y)cosx+sin(x+y)sinx
3cos(2x+y)+5cosy
=8cos(x+y)cosx+2sin(x+y)sinx=0
tan(x+y)tanx=-4
=cos(x+y)cosx-sin(x+y)sinx
cosy=cos[(x+y)-x]
=cos(x+y)cosx+sin(x+y)sinx
3cos(2x+y)+5cosy
=8cos(x+y)cosx+2sin(x+y)sinx=0
tan(x+y)tanx=-4
已知3cos(2x+y)+5cosy=0,则tan(x+y)tanx的值是
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