0.25^(-1)*(根号3/2)^(1/2)*(27/4)^(1/4)+log2(1/5)*log3(1/8)*log
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0.25^(-1)*(根号3/2)^(1/2)*(27/4)^(1/4)+log2(1/5)*log3(1/8)*log5(1/9)
![0.25^(-1)*(根号3/2)^(1/2)*(27/4)^(1/4)+log2(1/5)*log3(1/8)*log](/uploads/image/z/541270-46-0.jpg?t=0.25%5E%28-1%29%2A%28%E6%A0%B9%E5%8F%B73%2F2%29%5E%281%2F2%EF%BC%89%2A%EF%BC%8827%2F4%EF%BC%89%5E%281%2F4%29%2Blog2%281%2F5%29%2Alog3%281%2F8%29%2Alog)
0.25^(-1)*(根号3/2)^(1/2)*(27/4)^(1/4)=(1/4)^(-1)*(3/4)^(1/4)*(27/4)^(1/4)=4*3/2=6
log2(1/5)*log3(1/8)*log5(1/9)=(-lg5/lg2)(-lg8/lg2)(-lg9/lg2)=-6
所以结果为0
log2(1/5)*log3(1/8)*log5(1/9)=(-lg5/lg2)(-lg8/lg2)(-lg9/lg2)=-6
所以结果为0
0.25^(-1)*(根号3/2)^(1/2)*(27/4)^(1/4)+log2(1/5)*log3(1/8)*log
log2(3)*log3(4)*log4(5)*.log(k+1)(k+2)=log2(k+2) 怎么证
(-27/8)^3+(2-根号三)^0-1/9*log2^9*log3^4等于多少
log3^36-log3^4+log2(log2^16)+8^2/3+(27/8)^-1/3+log8^27/log4^
log根号2^(x-5)log2^(x-1)
(log2(5)+log4(125))×log3(2)/log根号3(5)
(log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7)
(log2 5+log4 125)log3 2/ log根号3 5
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log
log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=?
log根号2^(x-5)-log2^(x-1)
[log(3)3^1/2]^2+log(0.25)1/4+9log5根号5-log(根号3)1=?