(log2(5)+log4(125))×log3(2)/log根号3(5)
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/16 07:06:59
(log2(5)+log4(125))×log3(2)/log根号3(5)
![(log2(5)+log4(125))×log3(2)/log根号3(5)](/uploads/image/z/4073791-31-1.jpg?t=%28log2%285%EF%BC%89%2Blog4%EF%BC%88125%EF%BC%89%EF%BC%89%C3%97log3%EF%BC%882%EF%BC%89%2Flog%E6%A0%B9%E5%8F%B73%EF%BC%885%EF%BC%89)
原式=(log2(5)+(3/2)log2(5))×log3(2)/(2log3(5))
=(5/2)log2(5)))×(1/2)log5(2)
=5/4
=(5/2)log2(5)))×(1/2)log5(2)
=5/4
(log2(5)+log4(125))×log3(2)/log根号3(5)
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log
(log2 5+log4 125)log3 2/ log根号3 5
[log3(4)+log根下3(2)][log2(9)+log4(根3)]
(log2^5+log4^125)(log3^2)/(log(根号3)^5 要具体的过程,
0.25^(-1)*(根号3/2)^(1/2)*(27/4)^(1/4)+log2(1/5)*log3(1/8)*log
(log2(5)+log4(125))(log3(2)/log√3(5))怎么解?
(log2 3+log4 27)(log3 4+log27 16)
计算(log4 3+ log8 3)(log3 2+ log9 2)-- log1/2 32^(1/3)+5^(log2
利用换底公式求值:1.log2 25 ×log3 4 ×log5 9 2.(log4 3+log8 3)(log3 2+
log2(20)-log2(5)+2log3(2)×log4(3)
log2(3)*log3(4)*log4(5)*.log(k+1)(k+2)=log2(k+2) 怎么证