当x=根号2+1时,求(x-3/x^2-1)/(x-3/(x+1)^2)-(1/x-1)
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当x=根号2+1时,求(x-3/x^2-1)/(x-3/(x+1)^2)-(1/x-1)
![当x=根号2+1时,求(x-3/x^2-1)/(x-3/(x+1)^2)-(1/x-1)](/uploads/image/z/4871404-28-4.jpg?t=%E5%BD%93x%3D%E6%A0%B9%E5%8F%B72%2B1%E6%97%B6%2C%E6%B1%82%28x-3%2Fx%5E2-1%29%2F%28x-3%2F%28x%2B1%29%5E2%29-%281%2Fx-1%29)
原式=(x-3)/(x+1)(x-1)*(x+1)²/(x-3)-1/(x-1)
=(x+1)/(x-1)-1/(x-1)
=x/(x-1)
=(√2+1)/(√2-1-1)
=(√2+1)/√2
=(2+√2)/2
=(x+1)/(x-1)-1/(x-1)
=x/(x-1)
=(√2+1)/(√2-1-1)
=(√2+1)/√2
=(2+√2)/2
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