设数列{an}的前n项和为Sn,且对任意正整数n,an+Sn=4096若数列{log2底an}的前n项和记为f(n),求
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设数列{an}的前n项和为Sn,且对任意正整数n,an+Sn=4096若数列{log2底an}的前n项和记为f(n),求函数最大
![设数列{an}的前n项和为Sn,且对任意正整数n,an+Sn=4096若数列{log2底an}的前n项和记为f(n),求](/uploads/image/z/326871-63-1.jpg?t=%E8%AE%BE%E6%95%B0%E5%88%97%7Ban%7D%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8C%E4%B8%BASn%2C%E4%B8%94%E5%AF%B9%E4%BB%BB%E6%84%8F%E6%AD%A3%E6%95%B4%E6%95%B0n%2Can%2BSn%3D4096%E8%8B%A5%E6%95%B0%E5%88%97%EF%BD%9Blog2%E5%BA%95an%EF%BD%9D%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8C%E8%AE%B0%E4%B8%BAf%EF%BC%88n%EF%BC%89%2C%E6%B1%82)
an+Sn=4096
a(n-1)+S(n-1)=4096
两式相减 ==>> an=a(n-1) /2 (又a1+s1=4096 => a1=2048)
==>> an=2^(12-n) ==>> bn=(log2底an) = 12-n
f(n)=(11+12-n)*n/2
f(n)MAX =66
a(n-1)+S(n-1)=4096
两式相减 ==>> an=a(n-1) /2 (又a1+s1=4096 => a1=2048)
==>> an=2^(12-n) ==>> bn=(log2底an) = 12-n
f(n)=(11+12-n)*n/2
f(n)MAX =66
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