int[][4]={1,2,3,4,5,6,7,8};int(*p)[4]=a;则表达式**(p+1)-*(*p+1)的
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int[][4]={1,2,3,4,5,6,7,8};int(*p)[4]=a;则表达式**(p+1)-*(*p+1)的值是?
![int[][4]={1,2,3,4,5,6,7,8};int(*p)[4]=a;则表达式**(p+1)-*(*p+1)的](/uploads/image/z/2793783-39-3.jpg?t=int%5B%5D%5B4%5D%3D%7B1%2C2%2C3%2C4%2C5%2C6%2C7%2C8%7D%3Bint%28%2Ap%29%5B4%5D%3Da%3B%E5%88%99%E8%A1%A8%E8%BE%BE%E5%BC%8F%2A%2A%EF%BC%88p%2B1%EF%BC%89-%2A%28%2Ap%2B1%29%E7%9A%84)
记住一个万能公式就行了:
*(p + i) = p[i]
所以:
**(p+1) = *(*(p+1)) = *(p[1]) = *(p[1] + 0) = p[1][0] = 5;
*(*p + 1) = *(*(p + 0) + 1) = *(p[0] + 1) = p[0][1] = 2;
所以结果就是3了.
*(p + i) = p[i]
所以:
**(p+1) = *(*(p+1)) = *(p[1]) = *(p[1] + 0) = p[1][0] = 5;
*(*p + 1) = *(*(p + 0) + 1) = *(p[0] + 1) = p[0][1] = 2;
所以结果就是3了.
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