(cotα-1)/(2cotα+1)=1,(cos2α)/(1+sin2α)的值=?
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/13 07:36:37
(cotα-1)/(2cotα+1)=1,(cos2α)/(1+sin2α)的值=?
![(cotα-1)/(2cotα+1)=1,(cos2α)/(1+sin2α)的值=?](/uploads/image/z/19952216-8-6.jpg?t=%28cot%CE%B1-1%29%2F%282cot%CE%B1%2B1%29%3D1%2C%28cos2%CE%B1%29%2F%281%2Bsin2%CE%B1%29%E7%9A%84%E5%80%BC%3D%3F)
(cotα-1)/(2cotα+1)=1
cotα-1=2cotα+1
cotα=-2
tanα=-1/2
所以
(cos2α)/(1+sin2α)
=(1-tan²α)/(1+tan²α)】/(1+2tanα/(1+tan²α))
=(1-tan²α)/(1+tan²α+2tanα)
=(1-tanα)/(1+tanα)
=(1+1/2)/(1-1/2)
=3
cotα-1=2cotα+1
cotα=-2
tanα=-1/2
所以
(cos2α)/(1+sin2α)
=(1-tan²α)/(1+tan²α)】/(1+2tanα/(1+tan²α))
=(1-tan²α)/(1+tan²α+2tanα)
=(1-tanα)/(1+tanα)
=(1+1/2)/(1-1/2)
=3
已知tanθ=2,求sin2θ-cos2θ/1+cot²θ的值
高一数学证明(sin2α/1+cotα)+(cos2α/1+tanα)=1-sinαcosα
若tanα+cotβ=4,则sin2α=1/2的解法
已知sinα+cosα=2/3,求(1+cos2α)/[cot(α/2)-tan(α/2)]的值
证明2/(tanα-cotα)=sin2α/{(2sin^2)α-1}
sin2α+sin2β-sin2αsin2β+cos2αcos2β=1 证明
化简1+cos2αtanα2−cotα2的结果为( )
证明tanα+cotα=2/sin2α
求证tanα+cotα=2/sin2α
1)求证cotαcosα/cotα-cosα=tan(α/2+π/4)
证明恒等式1/4sin2α·(cotα/2-tanα/2)=cos²α
(sin2α-cos2α+1)/(1+tanα)=2sin2αcos2α 为什么