若|x-2|与(y+1/2)²互为相反数,试求代数式x²y-3xy²-1/3(3x
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若|x-2|与(y+1/2)²互为相反数,试求代数式x²y-3xy²-1/3(3x²y-2 xy²)的值
|x-2|与(y+1/2)²互为相反数
|x-2|+(y+1/2)²=0
x=2 y=-1/2
x²y-3xy²-1/3(3x²y-2 xy²)
=x²y-3xy²-3x²y+2 xy²/3
=-2x²y-7 xy²/3
=-2*2^2*(-1/2)-7*2*(-1/2)^2/3
=4-7/6
=17/6
|x-2|+(y+1/2)²=0
x=2 y=-1/2
x²y-3xy²-1/3(3x²y-2 xy²)
=x²y-3xy²-3x²y+2 xy²/3
=-2x²y-7 xy²/3
=-2*2^2*(-1/2)-7*2*(-1/2)^2/3
=4-7/6
=17/6
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