搜搜做题作业网计算：[5xy^2(x^2-3xy)-(-3x^2y^2)^3]÷(5xy)^2
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计算：[5xy^2(x^2-3xy)-(-3x^2y^2)^3]÷(5xy)^2
![计算：[5xy^2(x^2-3xy)-(-3x^2y^2)^3]÷(5xy)^2](/uploads/image/z/98698-58-8.jpg?t=%E8%AE%A1%E7%AE%97%EF%BC%9A%5B5xy%5E2%28x%5E2-3xy%29-%28-3x%5E2y%5E2%29%5E3%5D%C3%B7%285xy%29%5E2)
[5xy^2(x^2-3xy)-(-3x^2y^2)^3]/(5xy^2)
=[5xy^2(x^2-3xy)+27x^6y^6]/(5xy^2)
=5xy^2(x^2-3xy)/(5xy^2)+27x^6y^6/(5xy^2)
=x^2-3xy+27x^5y^4/5
再问： 和答案不一样哦！
再答： [5xy^2(x^2-3xy)-(-3x^2y^2)^3]/(25x^2y^2) =[5xy^2(x^2-3xy)+27x^6y^6]/(25x^2y^2) =(5x^3y^2-15x^2y^3+27x^6y^6)/(25x^2y^2)=(5x-15y+27x^4y^4)/25=x/5-(3y)/5+(27x^4y^4)/25
=[5xy^2(x^2-3xy)+27x^6y^6]/(5xy^2)
=5xy^2(x^2-3xy)/(5xy^2)+27x^6y^6/(5xy^2)
=x^2-3xy+27x^5y^4/5
再问： 和答案不一样哦！
再答： [5xy^2(x^2-3xy)-(-3x^2y^2)^3]/(25x^2y^2) =[5xy^2(x^2-3xy)+27x^6y^6]/(25x^2y^2) =(5x^3y^2-15x^2y^3+27x^6y^6)/(25x^2y^2)=(5x-15y+27x^4y^4)/25=x/5-(3y)/5+(27x^4y^4)/25
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