sin(x^2+y^2)=x,求dy
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sin(x^2+y^2)=x,求dy
![sin(x^2+y^2)=x,求dy](/uploads/image/z/966023-71-3.jpg?t=sin%28x%5E2%2By%5E2%29%3Dx%2C%E6%B1%82dy)
sin(x^2+y^2)=x
两边同时求导,得
(x^2+y^2)'cos(x^2+y^2)=dx
(2xdx+2ydy)cos(x^2+y^2)=dx
2xdx+2ydy=dx/cos(x^2+y^2)
2ydy=dx/cos(x^2+y^2)-2xdx
dy=(dx/cos(x^2+y^2)-2xdx)/2y
两边同时求导,得
(x^2+y^2)'cos(x^2+y^2)=dx
(2xdx+2ydy)cos(x^2+y^2)=dx
2xdx+2ydy=dx/cos(x^2+y^2)
2ydy=dx/cos(x^2+y^2)-2xdx
dy=(dx/cos(x^2+y^2)-2xdx)/2y