解方程组2X+3Y+2Z=19 3X+2Y+2Z=17 2X+2Y+3Z=13求X,Y,Z的值
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解方程组2X+3Y+2Z=19 3X+2Y+2Z=17 2X+2Y+3Z=13求X,Y,Z的值
![解方程组2X+3Y+2Z=19 3X+2Y+2Z=17 2X+2Y+3Z=13求X,Y,Z的值](/uploads/image/z/965032-16-2.jpg?t=%E8%A7%A3%E6%96%B9%E7%A8%8B%E7%BB%842X%2B3Y%2B2Z%3D19+3X%2B2Y%2B2Z%3D17+2X%2B2Y%2B3Z%3D13%E6%B1%82X%2CY%2CZ%E7%9A%84%E5%80%BC)
这是初中学的数学题,解如下
设2X+3Y+2Z=19为A,3X+2Y+2Z=17为B,2X+2Y+3Z=13为C:
A化简为:Z=(19-2X-3Y)/2
把Z=(19-2X-3Y)/2代入B和C,得:
3X+2Y+2〈(19-2X-3Y)/2〉=17
2X+2Y+3〈(19-2X-3Y)/2〉=13
然后化简得:
X-Y=-2
2X+5Y=31
解二元一次方程得:
X=3,Y=5
再将X、Y代入A,得
2*3+3*5+2Z=19
解得,Z=-1
所以,X=3,Y=5,Z=-1
设2X+3Y+2Z=19为A,3X+2Y+2Z=17为B,2X+2Y+3Z=13为C:
A化简为:Z=(19-2X-3Y)/2
把Z=(19-2X-3Y)/2代入B和C,得:
3X+2Y+2〈(19-2X-3Y)/2〉=17
2X+2Y+3〈(19-2X-3Y)/2〉=13
然后化简得:
X-Y=-2
2X+5Y=31
解二元一次方程得:
X=3,Y=5
再将X、Y代入A,得
2*3+3*5+2Z=19
解得,Z=-1
所以,X=3,Y=5,Z=-1
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