解不等式 log1/5 (x+2)<log1/5 (2x-3)
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解不等式 log1/5 (x+2)<log1/5 (2x-3)
1/5是底数.
我的答案是x小于5,
1/5是底数.
我的答案是x小于5,
![解不等式 log1/5 (x+2)<log1/5 (2x-3)](/uploads/image/z/9462480-24-0.jpg?t=%E8%A7%A3%E4%B8%8D%E7%AD%89%E5%BC%8F+log1%2F5+%28x%2B2%29%EF%BC%9Clog1%2F5+%282x-3%29)
log1/5 (x+2)<log1/5 (2x-3)
=>
log1/5[(x+2)/(2x-3)]
x+2>0
2x-3>0
(x+2)/(2x-3)>1
=> x
=>
log1/5[(x+2)/(2x-3)]
x+2>0
2x-3>0
(x+2)/(2x-3)>1
=> x
解不等式 log1/5 (x+2)<log1/5 (2x-3)
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