求极限lim x→π/2 (1-sinx)/(cos^2)x
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求极限lim x→π/2 (1-sinx)/(cos^2)x
如图.
请说明计算时使用的公式名称.
![](http://img.wesiedu.com/upload/1/5d/15dee2490bfa285c2eab9e4d7ef20043.jpg)
如图.
请说明计算时使用的公式名称.
![](http://img.wesiedu.com/upload/1/5d/15dee2490bfa285c2eab9e4d7ef20043.jpg)
![求极限lim x→π/2 (1-sinx)/(cos^2)x](/uploads/image/z/9241540-52-0.jpg?t=%E6%B1%82%E6%9E%81%E9%99%90lim+x%E2%86%92%CF%80%2F2+%281-sinx%29%2F%28cos%5E2%29x)
lim(x→π/2)(1-sinx)/(cosx)^2
=lim(x→π/2)(1-sinx)/[1-(sinx)^2]
=lim(x→π/2)(1-sinx)/[(1-sinx)(1+sinx)]
=lim(x→π/2)[1/(1+sinx)]
=1/2
没用什么公式,有不懂的,再补充吧……
=lim(x→π/2)(1-sinx)/[1-(sinx)^2]
=lim(x→π/2)(1-sinx)/[(1-sinx)(1+sinx)]
=lim(x→π/2)[1/(1+sinx)]
=1/2
没用什么公式,有不懂的,再补充吧……
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