根据图形填空:AD+( )+BC+( )=AC+( )=AB+( )AB=AD-( )AC=AD-( )=BC+( )B
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/24 17:35:44
根据图形填空:
AD+( )+BC+( )=AC+( )=AB+( )
AB=AD-( )
AC=AD-( )=BC+( )
BD-CD+AB=( )
![根据图形填空:AD+( )+BC+( )=AC+( )=AB+( )AB=AD-( )AC=AD-( )=BC+( )B](/uploads/image/z/9188249-41-9.jpg?t=%E6%A0%B9%E6%8D%AE%E5%9B%BE%E5%BD%A2%E5%A1%AB%E7%A9%BA%EF%BC%9AAD%2B%28+%29%2BBC%2B%28+%29%3DAC%2B%28+%29%3DAB%2B%28+%29AB%3DAD-%28+%29AC%3DAD-%28+%29%3DBC%2B%28+%29B)
AD+( )+BC+( )=AC+( )=AB+( )
AB=AD-( BD)
AC=AD-(CD )=BC+(AB )
BD-CD+AB=(AC )
AB=AD-( BD)
AC=AD-(CD )=BC+(AB )
BD-CD+AB=(AC )
根据图形填空:AD+( )+BC+( )=AC+( )=AB+( )AB=AD-( )AC=AD-( )=BC+( )B
在三角形ABC中,AD垂直BC,AB*CD=AC*AD 求 BC*AD=AC*AB
在梯形ABCD中,AD//BC,AB=CD=AD,AC=BC.
已知AB/AD=AC/AE=BC/DE,试说明AB*CE=AC*BD
已知AB+BD=AC+CD,AD⊥BC 证明AB=AC
已知D是AB上一点,且AC=AD,求证BC-CD<AB-AC
已知AB/AD=AC/AE=BC/DE.试说明AD*CE=BD*AE
已知在三角形abc中,ad垂直bc ab+ ad=ac +dc 求ab =ac
如图,已知AD//BC,AD=BC,AE⊥AD,AF⊥AB,AE=AD,AB=AF.求证:AC=EF.
如图,AD∥BC,AD=BC,AE⊥AD,AF⊥AB,且AE=AD,AF=AB,求证:AC=EF.
请给出解题思路,BC/AB=AC/AD 求出AD是4.62.我会了,
设平面上四点A,B,C,D,求证AB*CD+AD*BC>=AC*BD