已知若5x²-3x-5=0,求:(1)5x²-2x-1/(5x²-2x-5);(2)x
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已知若5x²-3x-5=0,求:(1)5x²-2x-1/(5x²-2x-5);(2)x²+x^-2
![已知若5x²-3x-5=0,求:(1)5x²-2x-1/(5x²-2x-5);(2)x](/uploads/image/z/912571-43-1.jpg?t=%E5%B7%B2%E7%9F%A5%E8%8B%A55x%26%23178%3B-3x-5%3D0%2C%E6%B1%82%EF%BC%9A%EF%BC%881%EF%BC%895x%26%23178%3B-2x-1%2F%285x%26%23178%3B-2x-5%29%EF%BC%9B%EF%BC%882%EF%BC%89x%26%23)
5x²-3x-5=0
等式两边同除以5x
x -3/5 -1/x=0
x- 1/x=3/5
5x²-3x-5=0
5x-2x-5=x
5x²-2x- 1/(5x²-2x-5)
=5x²-2x -5 -1/(5x²-2x-5) +5
=x -1/x +5
=3/5 +5
=28/5
x²+ 1/x²=(x-1/x)²+2=(3/5)²+2=9/25 +2=59/25
等式两边同除以5x
x -3/5 -1/x=0
x- 1/x=3/5
5x²-3x-5=0
5x-2x-5=x
5x²-2x- 1/(5x²-2x-5)
=5x²-2x -5 -1/(5x²-2x-5) +5
=x -1/x +5
=3/5 +5
=28/5
x²+ 1/x²=(x-1/x)²+2=(3/5)²+2=9/25 +2=59/25
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