设f(x)=x^3-3/2(a+1)X^2+3ax+1,(2)若函数f(x)在区间(1,4)内单调递减,求a的取值范
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设f(x)=x^3-3/2(a+1)X^2+3ax+1,(2)若函数f(x)在区间(1,4)内单调递减,求a的取值范
![设f(x)=x^3-3/2(a+1)X^2+3ax+1,(2)若函数f(x)在区间(1,4)内单调递减,求a的取值范](/uploads/image/z/8849583-63-3.jpg?t=%E8%AE%BEf%28x%29%3Dx%5E3-3%2F2%28a%2B1%29X%5E2%2B3ax%2B1%2C%282%29%E8%8B%A5%E5%87%BD%E6%95%B0f%28x%29%E5%9C%A8%E5%8C%BA%E9%97%B4%281%2C4%29%E5%86%85%E5%8D%95%E8%B0%83%E9%80%92%E5%87%8F%2C%E6%B1%82a%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83)
f'(x)=3x^2-3(a+1)x+3a=3[x^2-(a+1)x+a]=3(x-a)(x-1)
令f'(x)=4
令f'(x)=4
设f(x)=x^3-3/2(a+1)X^2+3ax+1,(2)若函数f(x)在区间(1,4)内单调递减,求a的取值范
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