求证 sinx(cos^2 2x-sin^2 2x) + 2cosx cos2x sin2x= sin 5x
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/08/17 10:40:12
求证 sinx(cos^2 2x-sin^2 2x) + 2cosx cos2x sin2x= sin 5x
![求证 sinx(cos^2 2x-sin^2 2x) + 2cosx cos2x sin2x= sin 5x](/uploads/image/z/8838281-65-1.jpg?t=%E6%B1%82%E8%AF%81+sinx%28cos%5E2+2x-sin%5E2+2x%29+%2B+2cosx+cos2x+sin2x%3D+sin+5x)
sinx(cos^2 2x-sin^2 2x) + 2cosx cos2x sin2x
=sinxcos4x+cosxsin4x
=sin(x+4x)
=sin5x
=sinxcos4x+cosxsin4x
=sin(x+4x)
=sin5x
求证 sinx(cos^2 2x-sin^2 2x) + 2cosx cos2x sin2x= sin 5x
sinx-2cosx=0.求sin2x-cos2x/1+sin^2x
已知:sinx-2cosx=0,求sin2x-cos2x/1+sin平方x
化简:2cos2x+2sin^2 x+cos(-x)分之sin2x+sin(π-x)=___________
求证:cosx+cos2x+...+cosnx={[cos(n+1)x/2]*[sin(n/2)x]}/[sin(x/2
求证:Sin^2 x / (sinx-cosx) - (sin x + cos x)/(ta
sinx+cosx/sinx-cosx=2 求sinx/cos^3x +cosx/sin^3x
求证 sin^2x/(sinx-cosx)-(sinx+cosx)/tan^2 x-1=sinx+cosx
1-2sinx cosx /COS^2X-SIN^2X =1-tanx/1+tanx 求证
求证 cos^8(x)-sin^8(x)=cos2x【1-1/2sin^2(2x)】
已知sin^2x+sin2x*sinx+cos2x=1,x属于(0,派/2),求tan2x
已知2sin²x-cos²x+sinxcosx-4sinx+2cosx=0求(sin2x+1)/(1