已知(x-1)²+丨y+2丨=0 求代数式2x²+(-x²-2xy+2y²)-2
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已知(x-1)²+丨y+2丨=0 求代数式2x²+(-x²-2xy+2y²)-2(x²-xy+2y²)的值
已知(x-1)²+丨y+2丨=0 求代数式2x²+(-x²-2xy+2y²)-2(x²-xy+2y²)的值
已知(x-1)²+丨y+2丨=0 求代数式2x²+(-x²-2xy+2y²)-2(x²-xy+2y²)的值
![已知(x-1)²+丨y+2丨=0 求代数式2x²+(-x²-2xy+2y²)-2](/uploads/image/z/8501758-70-8.jpg?t=%E5%B7%B2%E7%9F%A5%28x-1%29%26%23178%3B%2B%E4%B8%A8y%2B2%E4%B8%A8%3D0+%E6%B1%82%E4%BB%A3%E6%95%B0%E5%BC%8F2x%26%23178%3B%2B%28-x%26%23178%3B-2xy%2B2y%26%23178%3B%29-2)
(x-1)²+丨y+2丨=0
所以x-1=0,y+2=0
x=1,y=-2
所以原式=2x²-x²-2xy+2y²-2x²+2xy-4y²
=-x²-2y²
=-1-8
=-9
所以x-1=0,y+2=0
x=1,y=-2
所以原式=2x²-x²-2xy+2y²-2x²+2xy-4y²
=-x²-2y²
=-1-8
=-9
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