计算:(√48+√27-√12)÷√6 (3√5+2√3)(3√5-2√3) (2√7-3)²
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/08/15 08:47:40
计算:(√48+√27-√12)÷√6 (3√5+2√3)(3√5-2√3) (2√7-3)²
三道带根号的计算题,愁死我了,TMD都不会做,
三道带根号的计算题,愁死我了,TMD都不会做,
![计算:(√48+√27-√12)÷√6 (3√5+2√3)(3√5-2√3) (2√7-3)²](/uploads/image/z/8457886-46-6.jpg?t=%E8%AE%A1%E7%AE%97%3A%28%E2%88%9A48%2B%E2%88%9A27-%E2%88%9A12%29%C3%B7%E2%88%9A6+%EF%BC%883%E2%88%9A5%2B2%E2%88%9A3%EF%BC%89%EF%BC%883%E2%88%9A5-2%E2%88%9A3%EF%BC%89+%EF%BC%882%E2%88%9A7-3%EF%BC%89%26%23178%3B)
计算:
(√48+√27-√12)÷√6
=(4√3+3√3-2√3)÷√6
=5√3÷√6
=5/2√2
(3√5+2√3)(3√5-2√3)
=(3√5)²-(2√3)²
=45-12
=33
(2√7-3)²
=(2√7)²-2×2√7×3+3²
=28-12√7+9
=37-12√7
(√48+√27-√12)÷√6
=(4√3+3√3-2√3)÷√6
=5√3÷√6
=5/2√2
(3√5+2√3)(3√5-2√3)
=(3√5)²-(2√3)²
=45-12
=33
(2√7-3)²
=(2√7)²-2×2√7×3+3²
=28-12√7+9
=37-12√7
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