y=x/(√a²-x²),求dy/dx!

来源：学生作业帮编辑：搜搜做题作业网作业帮分类：数学作业时间：2024/08/12 08:55:46

dy/dx=[x/√(a²-x²)]'
=[√(a²-x²)+x²/√(a²-x²)]/(a²-x²)
=[(a²-x²)+x²]/(a²-x²)^(3/2)
=a²/(a²-x²)^(3/2).

y=x/(√a²-x²),求dy/dx! x-y²+xe^y=10 求dy/dx y=1/2·x·√(ln[x+²√(x²﹢a²)],求dy/dx及d²y/dx& dy/dx=-x/y 求通解求dy/dx= - x/y y=(sinx)^x 求DY/DX y=x+lnx,求dx/dy y=x^sinx求dy/dx tany=x+y 求dy/dx (dy/dx)-y=x求微分方程已知dx/dy=1/y’ 求d²x/dy² y=1+xe^y,求dy/dx.参数方程x=e^-t,y=3t,求dy/dx.求∫1/x+x².