1/(x^2-x)+1/(x^2-3x+2)=3/(2x-x^2)解分式方程,
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1/(x^2-x)+1/(x^2-3x+2)=3/(2x-x^2)解分式方程,
![1/(x^2-x)+1/(x^2-3x+2)=3/(2x-x^2)解分式方程,](/uploads/image/z/8406047-47-7.jpg?t=1%2F%28x%5E2-x%29%2B1%2F%28x%5E2-3x%2B2%29%3D3%2F%282x-x%5E2%29%E8%A7%A3%E5%88%86%E5%BC%8F%E6%96%B9%E7%A8%8B%2C)
1/x(x-1)+1/(x-2)(x-1)=-3/x(x-2)
乘以公因式:x(x-1)(x-2)
(x-2)+x(x-1)=-3(x-1)
x^2-5+3x=0
(x+3/2)^2=29/4
x1=(根号下29 -3)/2
x2= -(根号下29 +3)/2
乘以公因式:x(x-1)(x-2)
(x-2)+x(x-1)=-3(x-1)
x^2-5+3x=0
(x+3/2)^2=29/4
x1=(根号下29 -3)/2
x2= -(根号下29 +3)/2
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