运用两边夹定理证明极限(1/(n^2+1/(n^2+1)+1/(n^2+2)+...+1/(n^2+n)的极限=0
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运用两边夹定理证明极限(1/(n^2+1/(n^2+1)+1/(n^2+2)+...+1/(n^2+n)的极限=0
![运用两边夹定理证明极限(1/(n^2+1/(n^2+1)+1/(n^2+2)+...+1/(n^2+n)的极限=0](/uploads/image/z/8279623-55-3.jpg?t=%E8%BF%90%E7%94%A8%E4%B8%A4%E8%BE%B9%E5%A4%B9%E5%AE%9A%E7%90%86%E8%AF%81%E6%98%8E%E6%9E%81%E9%99%90%281%2F%28n%5E2%2B1%2F%28n%5E2%2B1%29%2B1%2F%28n%5E2%2B2%29%2B...%2B1%2F%28n%5E2%2Bn%29%E7%9A%84%E6%9E%81%E9%99%90%3D0)
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1/n=(1/(n^2)+1/(n^2)+...+1/(n^2))
=
1/n=(1/(n^2)+1/(n^2)+...+1/(n^2))
=
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