84÷63X3 1X5.3+2.1X6.2-2.1X1.5
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84÷63X3 1X5.3+2.1X6.2-2.1X1.5
﹙1﹚84÷63×3
=21×4÷21÷3×3
=4×﹙21÷21﹚×﹙3÷3﹚
=4
﹙2﹚1×5.3+2.1×6.2-2.1×1.5
=5.3+2.1×﹙6.2-1.5﹚
=5.3+2.1×4.7
=5.3+4.7+1.1×4.7
=10+5.17
=15.17.
=21×4÷21÷3×3
=4×﹙21÷21﹚×﹙3÷3﹚
=4
﹙2﹚1×5.3+2.1×6.2-2.1×1.5
=5.3+2.1×﹙6.2-1.5﹚
=5.3+2.1×4.7
=5.3+4.7+1.1×4.7
=10+5.17
=15.17.
84÷63X3 1X5.3+2.1X6.2-2.1X1.5
1x1-2x2+3x3-4x4+5x5-6x6.-100x100+101x101
宝马的 1 3 5 6 7 x3 x5 x6...
求编程高手.求x1+2*x2+3*x3+4*x4+5*x5+9*x6的最小值
解方程组X2+X3+X4=1 X1+X2+X3=5 X3+X4+X5=-5 X4+X5+X1=-3 X5+X1+X2=2
(x1,x2,x3,x4,x5,x6)来自正态总体N(0,1),Y=(x1+x2+x3)^2+(x4)^2+(x5)^2
有整数x1,x2,x3,x4,x5,x6,x7.x1
已知一组数据X1,X2,X3,X4,X5,X6的平均数是2,方差是1/2(急用)
设X1,X2,X3,X4,X5,X6是来自总体N(0,1)的样本,为什么X1+X2+X3~N(0,3)?
)设X服从N(0,1),(X1,X2,X3,X4,X5,X6)为来自总体X的简单随机样本,Y=(X1+X2+X3+)^2
解一道方程组x1+x2+x3=5,x2+x3+x4=1,x3+x4+x5=-5,x4+x5+x1=-3,x5+x1+x2
X1 - X3 - X4 -5X5=0 X1+2X2+3X3+3X4+7X5=0 X1+X2+X3+X4+X5=0 X2