证明:log(a)M*log(b)N=log(a)N*log(b)M.对调真数的位置,对数的积不变.
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证明:log(a)M*log(b)N=log(a)N*log(b)M.对调真数的位置,对数的积不变.
![证明:log(a)M*log(b)N=log(a)N*log(b)M.对调真数的位置,对数的积不变.](/uploads/image/z/8013696-24-6.jpg?t=%E8%AF%81%E6%98%8E%EF%BC%9Alog%28a%29M%2Alog%28b%29N%3Dlog%28a%29N%2Alog%28b%29M.%E5%AF%B9%E8%B0%83%E7%9C%9F%E6%95%B0%E7%9A%84%E4%BD%8D%E7%BD%AE%2C%E5%AF%B9%E6%95%B0%E7%9A%84%E7%A7%AF%E4%B8%8D%E5%8F%98.)
log(a)M*log(b)N
=lgM/lga*lgN/lgb
=(lgM/lgb)*(lgN/lga)
=log(a)N*log(b)M
=lgM/lga*lgN/lgb
=(lgM/lgb)*(lgN/lga)
=log(a)N*log(b)M
证明:log(a)M*log(b)N=log(a)N*log(b)M.对调真数的位置,对数的积不变.
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