∫(x^3 )*(sin x^2) dx 求不定积分

来源：学生作业帮编辑：搜搜做题作业网作业帮分类：数学作业时间：2024/07/29 21:00:24

解
∫x³sinx²dx
=1/2∫x²sinx²dx²
=1/2∫usinudu
=-1/2∫ud(cosu)
=-1/2[ucosu-∫cosudu]
=-1/2ucosu+1/2sinu+C
=-1/2x²cosx²+1/2sinx²+C

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