求值 3^2-log3(2)= log7(log5(log2(32)))=?
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求值 3^2-log3(2)= log7(log5(log2(32)))=?
3^2-log3(2)=
=3^2/3^(log3(2))
=9/2
log7(log5(log2(32)))
=log7(log5(5))
=log7 (1)
=0
=3^2/3^(log3(2))
=9/2
log7(log5(log2(32)))
=log7(log5(5))
=log7 (1)
=0
求值 3^2-log3(2)= log7(log5(log2(32)))=?
我是这样做的log2(3)*log3(5)*log5(49)*log7(64)=log2(3)*log3(5)*2log
log2(3)*log3(4)*log4(5)*log5(6)*log6(7)*log7(8)=?
log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=?
log2^25*log3^2倍根号2*log5^9=
log2^5*log3^2倍根号2*log5^9=
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log
(log3^4+log5^2)(log2^9+log2^根号3)
利用换底公式求值:1.log2 25 ×log3 4 ×log5 9 2.(log4 3+log8 3)(log3 2+
数学(log5 √2*log7 9)/(log5 1/3 *log7 3√4)+log2( √(3+√5)- log√(
log2为底3*log3为底4*log4为底5log5底6*log6底7*log7底8=
log2(3)+log3(5)+log3(2)=?