已知x+y=0.2,x+3y=1.求3X²+12XY+12Y²
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已知x+y=0.2,x+3y=1.求3X²+12XY+12Y²
![已知x+y=0.2,x+3y=1.求3X²+12XY+12Y²](/uploads/image/z/7571888-8-8.jpg?t=%E5%B7%B2%E7%9F%A5x%2By%3D0.2%2Cx%2B3y%3D1.%E6%B1%823X%26%23178%3B%2B12XY%2B12Y%26%23178%3B)
x+y=0.2,x+3y=1.
两式相减得,2Y=0.8,Y=0.4,X=-0.2
3X²+12XY+12Y²=3(x²+4xy+4y²)=3(x+2y)²=3(-0.2+0.8)²=1.08
两式相减得,2Y=0.8,Y=0.4,X=-0.2
3X²+12XY+12Y²=3(x²+4xy+4y²)=3(x+2y)²=3(-0.2+0.8)²=1.08
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