计算:(3a^(n+1)-6a^n+9a^(n-1)/(1/3a^(n-1)
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计算:(3a^(n+1)-6a^n+9a^(n-1)/(1/3a^(n-1)
![计算:(3a^(n+1)-6a^n+9a^(n-1)/(1/3a^(n-1)](/uploads/image/z/7466162-50-2.jpg?t=%E8%AE%A1%E7%AE%97%3A%283a%5E%28n%2B1%29-6a%5En%2B9a%5E%28n-1%29%2F%281%2F3a%5E%28n-1%29)
(3a^(n+1)-6a^n+9a^(n-1)/(1/3a^(n-1)
=3[3a^(n+1)-6a^n+9a^(n-1)]/a^(n-1)
=3[3an^(n-1)(a^2-2a+3)]/a^(n-1)
=3*3*(a^2-2a+3)
=9a²-18a+27
=3[3a^(n+1)-6a^n+9a^(n-1)]/a^(n-1)
=3[3an^(n-1)(a^2-2a+3)]/a^(n-1)
=3*3*(a^2-2a+3)
=9a²-18a+27
计算:(3a^n+2+6a^n+1-9^n)÷3a^n-1
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