用换元法解方程3x^2/(x^2-4x+4)-8x/(x-2)-3=0
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用换元法解方程3x^2/(x^2-4x+4)-8x/(x-2)-3=0
![用换元法解方程3x^2/(x^2-4x+4)-8x/(x-2)-3=0](/uploads/image/z/7442264-56-4.jpg?t=%E7%94%A8%E6%8D%A2%E5%85%83%E6%B3%95%E8%A7%A3%E6%96%B9%E7%A8%8B3x%5E2%2F%28x%5E2-4x%2B4%29-8x%2F%28x-2%29-3%3D0)
3x^2(x-2)^2-8x/(x-2)-3=0
令a=x/(x-2)
3a^2-8a-3=0
(3a+1)(a-3)=0
a=-1/3,a=3
x/(x-2)=-1/3
x-2=-3x
x
=1/2
x/(x-2)=3
x=3x-6
x=3
所以x=1/2,x=3
令a=x/(x-2)
3a^2-8a-3=0
(3a+1)(a-3)=0
a=-1/3,a=3
x/(x-2)=-1/3
x-2=-3x
x
=1/2
x/(x-2)=3
x=3x-6
x=3
所以x=1/2,x=3
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