=ln(1+t^2),y=arctant 求d²y/dx²的时候d/dt*(dy/dx)=-(1/2
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=ln(1+t^2),y=arctant 求d²y/dx²的时候d/dt*(dy/dx)=-(1/2t²)是怎么算出来的?
![=ln(1+t^2),y=arctant 求d²y/dx²的时候d/dt*(dy/dx)=-(1/2](/uploads/image/z/733222-46-2.jpg?t=%3Dln%EF%BC%881%2Bt%5E2%EF%BC%89%2Cy%3Darctant+%E6%B1%82d%26%23178%3By%2Fdx%26%23178%3B%E7%9A%84%E6%97%B6%E5%80%99d%2Fdt%2A%EF%BC%88dy%2Fdx%EF%BC%89%3D-%EF%BC%881%2F2)
直接对x求导算不出,所以先对t求导,再对x求导
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