已知y1=6-x,y2=2+7x,若①y1=2y2,求x的值;②当x取何值时,y1比y2小-3;③当x取何值时,y1与y
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已知y1=6-x,y2=2+7x,若①y1=2y2,求x的值;②当x取何值时,y1比y2小-3;③当x取何值时,y1与y2互为相反数?
![已知y1=6-x,y2=2+7x,若①y1=2y2,求x的值;②当x取何值时,y1比y2小-3;③当x取何值时,y1与y](/uploads/image/z/7322737-49-7.jpg?t=%E5%B7%B2%E7%9F%A5y1%3D6-x%EF%BC%8Cy2%3D2%2B7x%EF%BC%8C%E8%8B%A5%E2%91%A0y1%3D2y2%EF%BC%8C%E6%B1%82x%E7%9A%84%E5%80%BC%EF%BC%9B%E2%91%A1%E5%BD%93x%E5%8F%96%E4%BD%95%E5%80%BC%E6%97%B6%EF%BC%8Cy1%E6%AF%94y2%E5%B0%8F-3%EF%BC%9B%E2%91%A2%E5%BD%93x%E5%8F%96%E4%BD%95%E5%80%BC%E6%97%B6%EF%BC%8Cy1%E4%B8%8Ey)
①根据y1=2y2,∴6-x=2×2+14x,解得:x=
2
15.
②由y1比y2小-3,∴y1-y2=-3,∴6-x-2-7x=-3,解得:x=
1
8.
③由y1与y2互为相反数,∴y1+y2=0,∴6-x+7x+2=0,解得:x=−
4
3.
2
15.
②由y1比y2小-3,∴y1-y2=-3,∴6-x-2-7x=-3,解得:x=
1
8.
③由y1与y2互为相反数,∴y1+y2=0,∴6-x+7x+2=0,解得:x=−
4
3.
已知y1=6-x,y2=2+7x,若①y1=2y2,求x的值;②当x取何值时,y1比y2小-3;③当x取何值时,y1与y
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