设a-b=-2,求二分之a²;+b²减去ab的值 已知y+2x=1,求代数式(y+1²)-
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/08/06 18:07:46
设a-b=-2,求二分之a²;+b²减去ab的值 已知y+2x=1,求代数式(y+1²)-(y²-4x)的值
![设a-b=-2,求二分之a²;+b²减去ab的值 已知y+2x=1,求代数式(y+1²)-](/uploads/image/z/7254551-47-1.jpg?t=%E8%AE%BEa-b%3D-2%2C%E6%B1%82%E4%BA%8C%E5%88%86%E4%B9%8Ba%26%23178%3B%3B%2Bb%26%23178%3B%E5%87%8F%E5%8E%BBab%E7%9A%84%E5%80%BC+%E5%B7%B2%E7%9F%A5y%2B2x%3D1%2C%E6%B1%82%E4%BB%A3%E6%95%B0%E5%BC%8F%28y%2B1%26%23178%3B%EF%BC%89-)
a-b=-2
(a-b)^2=(-2)^2
(a-b)^2=4
(a^2+b^2)/2-ab
=(a^2+b^2-2ab)/2
=(a-b)^2/2
=4/2
=2
(y+1)^2-(y²-4x)
=y^2+2y+1-y^2+4x
=2y+4x+1
=2(y+2x)+1
y+2x=1
=2*1+1
=3
(a-b)^2=(-2)^2
(a-b)^2=4
(a^2+b^2)/2-ab
=(a^2+b^2-2ab)/2
=(a-b)^2/2
=4/2
=2
(y+1)^2-(y²-4x)
=y^2+2y+1-y^2+4x
=2y+4x+1
=2(y+2x)+1
y+2x=1
=2*1+1
=3
设a-b=-2,求二分之a²;+b²减去ab的值 已知y+2x=1,求代数式(y+1²)-
已知:a+b=2,ab=二分之三,求代数式a³b+ab³-2a²b²的值
已知,a(a-1)-(a²-b)=2,求代数式ab-二分之a²+b²的值.
已知a(a-1)-(a²-b)=4,求(二分之a²+b²)-ab的值
已知X,Y∈R+,求K=√x+√y/√(x+y)的最大值 设a,b∈R,且a^2+b^2=1,求ab及a+b的取值范围(
已知a(a-1)-(a²-b)=2,求式子(二分之a²+b²)-ab的值
已知:6x²-7xy-3y²+14x+y+a=(2x-3y+b)(3x+y+1)求a,b的值
已知x,y互为相反数,且x≠0,a,b互为倒数,|n|=2 求代数式x-n/ab-(-y)+y/x的值
已知,a(a-1)-(a²-b)=4,求代数式2/a²+b²-ab的值
已知|x-y-3|+(a+b+4)²=0,求2a+2b-(a+b)分之(x-y)²-3(y-x)的值
已知二分之a=三分之b≠0,求代数式5a-2b/a^2-2b^2*(a-2b)的值
x²(x+y)(y-x)-xy(x+y)(x-y) 已知a+b=4,ab=-2,求多项式3a²b+3