(20+2x)(40-x)=1200
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/16 10:42:13
(20+2x)(40-x)=1200
![(20+2x)(40-x)=1200](/uploads/image/z/7171877-29-7.jpg?t=%2820%2B2x%29%2840-x%29%3D1200)
(40-x)(20+2x)=1200
800+80X-20X-2x^2=1200
-2x^2+60X-400=0
x^2-30X+200=0
(X-10)(X-20)=0
X-10=0 X-20=0
X1=10 X2=20
800+80X-20X-2x^2=1200
-2x^2+60X-400=0
x^2-30X+200=0
(X-10)(X-20)=0
X-10=0 X-20=0
X1=10 X2=20
(X+X*20%)-[(1200-X)-(1200-X)*20%]=40%
X+X*20%-(1200-X)-(1200-X)*20%=40%
(20+2x)(40-x)=1200
(40-x)(20+2x)=1200
(40-x)(20+2x)=1200 800+80X-20X-2x^2=1200 -2x^2+60X-400=0 x^2
X-40%X+1200=2/3X怎么算
((20+2X)(40-x)==1200求解
x+3/20x=46 ,x-1/5x=40 ,x-1/2x=3/4 ,x-0.2x=18解方程
(20+2x)(40-x)=1200,怎样解,
(40-x)(20+2x)=1200
(20+2x)(40-x)=1200方程求解
(20-2x)(20-2x)x>400 x=?