三角化简sin(x-5兀)cos[(-兀/2)-x]cos(8兀-x)/sin[x-(3兀/2)]sin(-x-4兀)
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/17 11:18:04
三角化简
sin(x-5兀)cos[(-兀/2)-x]cos(8兀-x)/sin[x-(3兀/2)]sin(-x-4兀)
sin(x-5兀)cos[(-兀/2)-x]cos(8兀-x)/sin[x-(3兀/2)]sin(-x-4兀)
![三角化简sin(x-5兀)cos[(-兀/2)-x]cos(8兀-x)/sin[x-(3兀/2)]sin(-x-4兀)](/uploads/image/z/7084004-68-4.jpg?t=%E4%B8%89%E8%A7%92%E5%8C%96%E7%AE%80sin%28x-5%E5%85%80%29cos%5B%28-%E5%85%80%2F2%29-x%5Dcos%288%E5%85%80-x%29%2Fsin%5Bx-%283%E5%85%80%2F2%29%5Dsin%28-x-4%E5%85%80%29)
sin(x-900°)cos(-90°-x)cos(1440°-x)/sin(x-270°)sin(-x-720°)
=sin(-180°+x)cos(-90°-x)cos(-x)/sin(-270°+x)sin(-x)
=-sinx(-sinx)cosx/cosx(-sinx)
=-sinx
=sin(-180°+x)cos(-90°-x)cos(-x)/sin(-270°+x)sin(-x)
=-sinx(-sinx)cosx/cosx(-sinx)
=-sinx
三角化简sin(x-5兀)cos[(-兀/2)-x]cos(8兀-x)/sin[x-(3兀/2)]sin(-x-4兀)
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