圆内接正七边形A1A2A3A4A5A6A7,证明:1/A1A2=1/A1A3+1/A1A4
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圆内接正七边形A1A2A3A4A5A6A7,证明:1/A1A2=1/A1A3+1/A1A4
![圆内接正七边形A1A2A3A4A5A6A7,证明:1/A1A2=1/A1A3+1/A1A4](/uploads/image/z/6956415-63-5.jpg?t=%E5%9C%86%E5%86%85%E6%8E%A5%E6%AD%A3%E4%B8%83%E8%BE%B9%E5%BD%A2A1A2A3A4A5A6A7%2C%E8%AF%81%E6%98%8E%3A1%2FA1A2%3D1%2FA1A3%2B1%2FA1A4)
我回答过了:
因为是正七边形,所以A1=A2=A3=A4
所以1/a1a2=1/a1a3=1/a1a4
因为是正七边形,所以A1=A2=A3=A4
所以1/a1a2=1/a1a3=1/a1a4
圆内接正七边形A1A2A3A4A5A6A7,证明:1/A1A2=1/A1A3+1/A1A4
已知A1A2A3A4A5A6A7是圆内接正七边形,求证:1/边A1A2=1/边A1A3+1/边A1A4
已知A1A2A3A4A5A6A7是圆内接正七边形,求证:1/A1A2=1/A1A3+1/A1A4
设A1A2A3A4A5A6A7是圆内接正七边形,求证:1/A1A2=1/A1A3+1/A1A4 .
已知A1A2A3A4A5A6A7是圆内接正七边形,求证;1/A1A2=1/A1A3+1/A1A4
设A1A2A3.A7是圆内接正七边形,求证:1/(A1A2)等于1/(A1A3)+1/(A1A4)
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