已知实数a,b,c满足|a+1|+(b-5)^2+(25c^2+10c+1)=0,求(abc)^251/(a^11b^8
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已知实数a,b,c满足|a+1|+(b-5)^2+(25c^2+10c+1)=0,求(abc)^251/(a^11b^8c^
![已知实数a,b,c满足|a+1|+(b-5)^2+(25c^2+10c+1)=0,求(abc)^251/(a^11b^8](/uploads/image/z/6948050-50-0.jpg?t=%E5%B7%B2%E7%9F%A5%E5%AE%9E%E6%95%B0a%2Cb%2Cc%E6%BB%A1%E8%B6%B3%EF%BD%9Ca%2B1%EF%BD%9C%2B%EF%BC%88b-5%EF%BC%89%5E2%2B%2825c%5E2%2B10c%2B1%29%3D0%2C%E6%B1%82%28abc%29%5E251%2F%28a%5E11b%5E8)
解;由题意的|a+1|=0
(b-5)^2=0
25c^2+10c+1=0(因为delta=100-4×1×25=0)
所以a=-1,b=5,c=-1/5
所以原式=(-1×5×-1/5))^251/-1
=1 (后面的a^11b^8c^ 没给清楚)
(b-5)^2=0
25c^2+10c+1=0(因为delta=100-4×1×25=0)
所以a=-1,b=5,c=-1/5
所以原式=(-1×5×-1/5))^251/-1
=1 (后面的a^11b^8c^ 没给清楚)
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