Tn=log2[2^1]+log2[2^(-2)]+...+log[2^(4-3n)] =1-2-5+.+4-3n =(
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Tn=log2[2^1]+log2[2^(-2)]+...+log[2^(4-3n)] =1-2-5+.+4-3n =(1+4-3n)*3n/2 疑问:项数为什么是3n?
等差数列
a1=1
ak=4-3n
d=-3
所以项数k=(ak-a1)/d+1
=(3-3n)/(-3)+1
=n-1+1
=n
a1=1
ak=4-3n
d=-3
所以项数k=(ak-a1)/d+1
=(3-3n)/(-3)+1
=n-1+1
=n
Tn=log2[2^1]+log2[2^(-2)]+...+log[2^(4-3n)] =1-2-5+.+4-3n =(
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