已知x+y=4,xy=-12,求(1)x2+y2的值;(2)求(x-y)2的值.
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已知x+y=4,xy=-12,求(1)x2+y2的值;(2)求(x-y)2的值.
![已知x+y=4,xy=-12,求(1)x2+y2的值;(2)求(x-y)2的值.](/uploads/image/z/6634946-2-6.jpg?t=%E5%B7%B2%E7%9F%A5x%2By%3D4%EF%BC%8Cxy%3D-12%EF%BC%8C%E6%B1%82%EF%BC%881%EF%BC%89x2%2By2%E7%9A%84%E5%80%BC%EF%BC%9B%EF%BC%882%EF%BC%89%E6%B1%82%EF%BC%88x-y%EF%BC%892%E7%9A%84%E5%80%BC%EF%BC%8E)
∵x+y=4,xy=-12,
∴(1)x2+y2=(x+y)2-2xy=16+24=40;
(2)(x-y)2=(x+y)2-4xy=16+48=64.
∴(1)x2+y2=(x+y)2-2xy=16+24=40;
(2)(x-y)2=(x+y)2-4xy=16+48=64.
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