设全集为R,已知A={x丨-2<x<3},B={x²+2x-8>0},M={x丨x²-4ax+3a≤
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设全集为R,已知A={x丨-2<x<3},B={x²+2x-8>0},M={x丨x²-4ax+3a≤0},若CR(A∪B)⊂M,求实数a的取值范围.
![设全集为R,已知A={x丨-2<x<3},B={x²+2x-8>0},M={x丨x²-4ax+3a≤](/uploads/image/z/6621946-34-6.jpg?t=%E8%AE%BE%E5%85%A8%E9%9B%86%E4%B8%BAR%2C%E5%B7%B2%E7%9F%A5A%3D%EF%BD%9Bx%E4%B8%A8-2%EF%BC%9Cx%EF%BC%9C3%EF%BD%9D%2CB%3D%EF%BD%9Bx%26%23178%3B%2B2x-8%EF%BC%9E0%EF%BD%9D%2CM%3D%EF%BD%9Bx%E4%B8%A8x%26%23178%3B-4ax%2B3a%E2%89%A4)
一、先求AUB在全体实数R的补集
集合A是清楚的,现在来解集合B.
x^2+2x-8>0,即(x+1)^2>9,亦即:x+1>3或x+12,或x
集合A是清楚的,现在来解集合B.
x^2+2x-8>0,即(x+1)^2>9,亦即:x+1>3或x+12,或x
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