当(a -1)²+(b+3的绝对值)=0时,化简求值-a²b +(3ab ²-a²
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/25 19:45:07
当(a -1)²+(b+3的绝对值)=0时,化简求值-a²b +(3ab ²-a²b )-2(2ab ²-a²b )
![当(a -1)²+(b+3的绝对值)=0时,化简求值-a²b +(3ab ²-a²](/uploads/image/z/6505551-63-1.jpg?t=%E5%BD%93%EF%BC%88a+%EF%BC%8D1%EF%BC%89%26%23178%3B%EF%BC%8B%EF%BC%88b%EF%BC%8B3%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC%EF%BC%89%EF%BC%9D0%E6%97%B6%2C%E5%8C%96%E7%AE%80%E6%B1%82%E5%80%BC%EF%BC%8Da%26%23178%3Bb+%EF%BC%8B%EF%BC%883ab+%26%23178%3B%EF%BC%8Da%26%23178)
由题意可得:a-1=0,b+3=0
解得:a=1,b=-3
原式=-a^2b+3ab^2-a^2b-4ab^2+2a^2b
=(-1-1+2)a^2b+(3-4)ab^2
=-ab^2
=-1*(-3)^2
=-9
解得:a=1,b=-3
原式=-a^2b+3ab^2-a^2b-4ab^2+2a^2b
=(-1-1+2)a^2b+(3-4)ab^2
=-ab^2
=-1*(-3)^2
=-9
当(a -1)²+(b+3的绝对值)=0时,化简求值-a²b +(3ab ²-a²
先化简,再求值:a²-b²/a²+ab,其中a=1,b=-1
已知,a-2的绝对值与(b+1)²互为相反数,求5a²b-2ab²+3ab的值.
当3a²+ab-2b²=0(a≠0,b≠0)时,求a/b-b/a-﹙a²+b²﹚
先化简再求值 (a-2b)(a²+2ab+4b²)-a(a-5b)(a+3b),其中a=-1,b=2
已知a+b=4,ab=-1,求a+4ab+b 化简求值:(a+2b)(a-2b)-(2a-
先化简,再求值:-1/3(3a²-6ab)+[a²-1/2(2a+2ab)],当b=负1/2时,求值
先化简,在求值 ﹙a分之1+b分之1﹚·a²+2ab+b²分之ab.其中a=3,b=-2
(1)先化简,后求值:(a+b/a-b)²×2a-2b/3a+3b÷ab/a²-b²,其中
求:化简求值:5abc-2a²b+[3abc-2(4ab²-a²b)],其中a,b,c满足
有一道化简求值提:“当a=-2,b=-3时,求(3a的平方b-2ab)-(ab-4a的平方)+(3ab-a的平方b)的值
先化简,再求值:(2a-3b)(3b+2a)-(2a-3b)²,其中:a=-2,b=-1