实数x、y满足(1-i)x+(1+i)y=2,则xy的值是______.
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实数x、y满足(1-i)x+(1+i)y=2,则xy的值是______.
∵实数x、y满足(1-i)x+(1+i)y=2,即 x+y+(y-x)i=2,∴x+y=2,y-x=0,
解得 x=y=1,∴xy=1,
故答案为 1.
解得 x=y=1,∴xy=1,
故答案为 1.
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