已知a> 0,函数f(x)=-2asin(2x+ π/6)+2a+b,当x∈[0, π/2]时,-5≤ f(x)≤ 1.
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已知a> 0,函数f(x)=-2asin(2x+ π/6)+2a+b,当x∈[0, π/2]时,-5≤ f(x)≤ 1.求a,b的值 和答案对不到,帮帮忙了,谢谢阿
a是大于0的哦,还是写写了
a是大于0的哦,还是写写了
![已知a> 0,函数f(x)=-2asin(2x+ π/6)+2a+b,当x∈[0, π/2]时,-5≤ f(x)≤ 1.](/uploads/image/z/6316227-27-7.jpg?t=%E5%B7%B2%E7%9F%A5a%3E+0%2C%E5%87%BD%E6%95%B0f%28x%29%3D-2asin%282x%2B+%CF%80%2F6%29%2B2a%2Bb%2C%E5%BD%93x%E2%88%88%5B0%2C+%CF%80%2F2%5D%E6%97%B6%2C-5%E2%89%A4+f%28x%29%E2%89%A4+1.)
因为x∈[0, π/2]
所以2x+π/6∈[π/6,7π/6]
所以-1/2
所以2x+π/6∈[π/6,7π/6]
所以-1/2
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