这题咋做(3x-2)(2x+3)-(x-1)²
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这题咋做(3x-2)(2x+3)-(x-1)²
![这题咋做(3x-2)(2x+3)-(x-1)²](/uploads/image/z/6305256-0-6.jpg?t=%E8%BF%99%E9%A2%98%E5%92%8B%E5%81%9A%283x-2%29%282x%2B3%29-%28x-1%29%26%23178%3B)
解
(3x-2)(2x+3)-(x-1)²
=6x²+9x-4x-6-(x²-2x+1)
=(6x²-x²)+(5x+2x)+(-6-1)
=5x²+7x-7
(3x-2)(2x+3)-(x-1)²
=6x²+9x-4x-6-(x²-2x+1)
=(6x²-x²)+(5x+2x)+(-6-1)
=5x²+7x-7
(x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3
x-1)(X-2)(x-3)...(x-50)+x(x-2)(X-3)...(X-50)+...+x(x-1)(x-2)
6x+(2x²-3x)-(x²-1)
(2x²-2x+3)(-x³+x-1)
x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4
x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x
x²+3x+9/(x²-27)+6x/(9x-x²)-(x-1)/(6+2x)
1+x+x^2+x^3+.+x^99+x^100
这题咋做(3x-2)(2x+3)-(x-1)²
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①2(x+3)(x-3)=x²+(x-1)(x+1)+2x