计算:2/x+x²-1/x²-2x+1·x-1/x²+x;(1/a-3+1)÷a²
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/18 06:20:03
计算:2/x+x²-1/x²-2x+1·x-1/x²+x;(1/a-3+1)÷a²-4/2a-6.
![计算:2/x+x²-1/x²-2x+1·x-1/x²+x;(1/a-3+1)÷a²](/uploads/image/z/6092729-17-9.jpg?t=%E8%AE%A1%E7%AE%97%EF%BC%9A2%2Fx%2Bx%26%23178%3B-1%2Fx%26%23178%3B-2x%2B1%C2%B7x-1%2Fx%26%23178%3B%2Bx%EF%BC%9B%EF%BC%881%2Fa-3%2B1%EF%BC%89%C3%B7a%26%23178)
因为(x的平方-2x+1)/(x的平方-1)÷(x-1)/(x的平方+x)-x的值与x无关:
(x的平方-2x+1)/(x的平方-1)÷(x-1)/(x的平方+x)-x
=(x-1)^2/[(x+1)(x-1)] * x(x+1)/(x-1) -x
=x -x
=0
(x的平方-2x+1)/(x的平方-1)÷(x-1)/(x的平方+x)-x
=(x-1)^2/[(x+1)(x-1)] * x(x+1)/(x-1) -x
=x -x
=0
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