设siny-e^x+xy^2=0,求dy/dx
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设siny-e^x+xy^2=0,求dy/dx
![设siny-e^x+xy^2=0,求dy/dx](/uploads/image/z/603139-67-9.jpg?t=%E8%AE%BEsiny-e%5Ex%2Bxy%5E2%3D0%2C%E6%B1%82dy%2Fdx)
siny-e^x+xy^2=0
cosy.y' -e^x + 2xy.y' +y^2 =0
(cosy+2xy)y' = e^x-y^2
y' = (e^x-y^2)/(cosy+2xy)
cosy.y' -e^x + 2xy.y' +y^2 =0
(cosy+2xy)y' = e^x-y^2
y' = (e^x-y^2)/(cosy+2xy)
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