(log4^3+log8^3)*(log3^2+log9^2)-log2^4次√32
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/13 06:31:04
(log4^3+log8^3)*(log3^2+log9^2)-log2^4次√32
(log4^3+log8^3)*(log3^2+log9^2)-log2^(4√32)(那个4是根号上的)(log旁边的数字是在最下面的)
(log4^3+log8^3)*(log3^2+log9^2)-log2^(4√32)(那个4是根号上的)(log旁边的数字是在最下面的)
![(log4^3+log8^3)*(log3^2+log9^2)-log2^4次√32](/uploads/image/z/6006922-34-2.jpg?t=%28log4%5E3%2Blog8%5E3%29%2A%28log3%5E2%2Blog9%5E2%29-log2%5E4%E6%AC%A1%E2%88%9A32)
(log4^3+log8^3)*(log3^2+log9^2)-log2^(4√32)
=(log4^3*8^3)*(log3^2*9^2)-log2^(4√32)
=(log2^15)*(log3^6)-log2^(4√32)
=90*log2*log3 -(16√2)log2
=(log4^3*8^3)*(log3^2*9^2)-log2^(4√32)
=(log2^15)*(log3^6)-log2^(4√32)
=90*log2*log3 -(16√2)log2
(log4^3+log8^3)*(log3^2+log9^2)-log2^4次√32
1.log2 3*log3 4*log4 5*log5 2 2.(log4 3+log8 3)8(log3 2+log9
(log4^3+log8^3)(log3^2+log9^2)+log2^(32)的1/4次方
(log3^2 + log9^4)×(log4^3 + log8^3)
计算(log4 3+ log8 3)(log3 2+ log9 2)-- log1/2 32^(1/3)+5^(log2
[log2(3)+log4(9)][log3(4)+log9(2)]等于
计算:(log4 9+log8 3)(log3 2+log9 2)-log1/3 4√81
化简(log4(3)+log8(3))(log3(2)+log9(2))
(log4^3+log8^3)(log3^2+log9^2)
求值(log4(3)+log8(3))×(log3(2)+log9(2))
求值(log3(2)+log9(2))*(log4(3)+log8(3))
(log3 2+log9 2)*(log4 3+log8 3)求值