把1/2【sin2θ+cos(π/3-2θ)】-sinπ/12*cos(π/12+2θ)化简得?
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把1/2【sin2θ+cos(π/3-2θ)】-sinπ/12*cos(π/12+2θ)化简得?
求过程o(TヘTo)
求过程o(TヘTo)
![把1/2【sin2θ+cos(π/3-2θ)】-sinπ/12*cos(π/12+2θ)化简得?](/uploads/image/z/5955425-17-5.jpg?t=%E6%8A%8A1%2F2%E3%80%90sin2%CE%B8%2Bcos%28%CF%80%2F3-2%CE%B8%29%E3%80%91-sin%CF%80%2F12%2Acos%28%CF%80%2F12%2B2%CE%B8%29%E5%8C%96%E7%AE%80%E5%BE%97%3F)
sin2θ
再问: 求过程
再答:![](http://img.wesiedu.com/upload/e/d9/ed9029cf15d1d4531b4dcacd60e131be.jpg)
再问: 求过程
再答:
![](http://img.wesiedu.com/upload/e/d9/ed9029cf15d1d4531b4dcacd60e131be.jpg)
把1/2【sin2θ+cos(π/3-2θ)】-sinπ/12*cos(π/12+2θ)化简得?
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