解方程或不等式:(1)(x+3)2+2(x-1)2=3x2+13.(2)(2x-5)2+(3x+1)2>13(x2-10
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/14 06:10:34
解方程或不等式:
(1)(x+3)2+2(x-1)2=3x2+13.
(2)(2x-5)2+(3x+1)2>13(x2-10).
(1)(x+3)2+2(x-1)2=3x2+13.
(2)(2x-5)2+(3x+1)2>13(x2-10).
![解方程或不等式:(1)(x+3)2+2(x-1)2=3x2+13.(2)(2x-5)2+(3x+1)2>13(x2-10](/uploads/image/z/5827901-5-1.jpg?t=%E8%A7%A3%E6%96%B9%E7%A8%8B%E6%88%96%E4%B8%8D%E7%AD%89%E5%BC%8F%EF%BC%9A%EF%BC%881%EF%BC%89%EF%BC%88x%2B3%EF%BC%892%2B2%EF%BC%88x-1%EF%BC%892%3D3x2%2B13%EF%BC%8E%EF%BC%882%EF%BC%89%EF%BC%882x-5%EF%BC%892%2B%EF%BC%883x%2B1%EF%BC%892%EF%BC%9E13%EF%BC%88x2-10)
(1)整理得:x2+6x+9+2x2-4x+2=3x2+13,
移项合并得:2x=2,
解得:x=1;
(2)不等式整理得:4x2-20x+25+9x2+6x+1>13x2-130,
移项合并得:-14x>-156,
解得:x<11
1
7.
移项合并得:2x=2,
解得:x=1;
(2)不等式整理得:4x2-20x+25+9x2+6x+1>13x2-130,
移项合并得:-14x>-156,
解得:x<11
1
7.
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